Write an equation in slope-intercept for the line that goes through the points (3, -3) and (6, -2)..

Question

Write an equation in slope-intercept for the line that goes
through the points (3, -3) and (6, -2)..

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Xavia 4 years 2021-08-26T06:06:28+00:00 2 Answers 5 views 0

Answers ( )

  1. niczorrrr
    0
    2021-08-26T06:08:16+00:00
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    Answer:

    y = 1/3x – 4

    Step-by-step explanation:

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  2. thongdat2
    0
    2021-08-26T06:08:26+00:00
    Reply

    Answer:

    y = \frac{1}{3} x-4  

    Step-by-step explanation:

    1) First, find the slope of the line. Use the slope formula, m = \frac{y_2-y_1}{x_2-x_1}. Substitute the x and y values of the given points into the formula and solve:

    m=\frac{(-2)-(-3)}{(6)-(3)} \\m = \frac{-2+3}{6-3} \\m = \frac{1}{3}

    Thus, the slope is \frac{1}{3}.

    2) Next, write the equation of the line using the point-slope formula y-y_1 = m (x-x_1). (From there, we can convert it to slope-intercept form.) Substitute m, x_1, and y_1 for real values.

    Since m represents the slope, substitute \frac{1}{3} for it. Since x_1 and y_1 represent the x and y values of one point the line intersects, substitute the x and y values of either one of the given points (it doesn’t matter which one, it will equal the same thing) into the formula as well. I chose (3, -3), as shown below. From there, convert the point-slope form of the equation to slope-intercept form by isolating y:

    y-(-3) = \frac{1}{3} (x-3)\\y + 3=\frac{1}{3} x-1\\y = \frac{1}{3} x-4

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