While traveling on a horizontal road at speed vi, a driver sees a large rabbit ahead and slams on the brakes. The wheels lock and the car be

Question

While traveling on a horizontal road at speed vi, a driver sees a large rabbit ahead and slams on the brakes. The wheels lock and the car begins to slide against the road. The car collides with the rabbit at a final speed of vf, after T seconds of braking. What is the coefficient of kinetic friction of the tires against the road?

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Thu Cúc 3 years 2021-08-19T08:02:44+00:00 1 Answers 57 views 0

Answers ( )

  1. minhkhang
    0
    2021-08-19T08:04:04+00:00
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    Answer:

    μk = (Vf – Vc)/(T×g)

    Explanation:

    Given

    Vi = initial velocity of the car

    Vf = final velocity of the car

    T = Time of application of brakes

    g = acceleration due to gravity (known constant)

    Let the mass of the car be Mc

    Assuming only kinetic frictional force acts on the car as the driver applies the brakes,

    The n from Newtown’s second law of motion.

    Fk = Mc×a

    Fk = μk×Mc×g

    a = (Vf – Vc)/T

    Equating both preceding equation.

    μk×Mc×g = Mc × (Vf – Vc)/T

    Mc cancels out.

    μk = (Vf – Vc)/(T×g)

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