Which of the following is the standard form of (x-7)2 + (y +1)2 = 16?

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Which of the following is the standard form of (x-7)2 + (y +1)2 = 16?

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Ngọc Hoa 4 years 2021-09-01T00:29:59+00:00 1 Answers 19 views 0

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  1. vankhanh
    0
    2021-09-01T00:31:08+00:00
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    Answer:

    (x - 7) {}^{2} + (y + 1) {}^{2} = 16 \\ this \: is \: an \: equation \: of \: circle \\ ( {x}^{2} - 14x + 49) + ( {y}^{2} + 2y + 1) = 16 \\ {x}^{2} + {y}^{2} - 14x + 2y + 50 = 16 \\ {x}^{2} {y}^{2} - 14x + 2y + 34 = 0

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )