When a baseball is hit by a batter the height of the ball age of T at time TT equals zero is determined by the equation age of T equals -16

Question

When a baseball is hit by a batter the height of the ball age of T at time TT equals zero is determined by the equation age of T equals -16 T squared +64 2+ 4FT is in seconds for which interval of time is the height of the bar greater than or equal to 52 feet

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Xavia 4 years 2021-08-02T14:10:41+00:00 1 Answers 199 views 0

Answers ( )

  1. hongcuc2
    0
    2021-08-02T14:12:38+00:00
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    Answer:

    1 ≥ t ≤ 3

    Step-by-step explanation:

    Given

    h(t) = -16t² + 64t + 4

    Required

    Determine the interval which the bar is at a height greater than or equal to 52ft

    This implies that

    h(t) ≥ 52

    Substitute -16t² + 64t + 4 for h(t)

    -16t² + 64t + 4 ≥ 52

    Collect like terms

    -16t² + 64t + 4 – 52 ≥ 0

    -16t² + 64t – 48 ≥ 0

    Divide through by 16

    -t² + 4t – 3 ≥ 0

    Multiply through by -1

    t² – 4t + 3 ≤ 0

    t² – 3t – t + 3 ≤ 0

    t(t – 3) -1(t – 3) ≤ 0

    (t – 1)(t – 3) ≤ 0

    t – 1 ≤ 0 or t – 3 ≤ 0

    t ≤ 1 or t ≤ 3

    Rewrite as:

    1 ≥ t or t ≤ 3

    Combine inequality

    1 ≥ t ≤ 3

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )