What is the relative atomic mass of an element whose isotopic composition is 90% of 20x and 10% of 22x ​

Question

What is the relative atomic mass of an element
whose isotopic composition is 90% of 20x and 10% of 22x
​

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Tryphena 4 years 2021-09-01T01:06:12+00:00 1 Answers 597 views 1

Answers ( )

  1. thucuc
    1
    2021-09-01T01:08:00+00:00
    Reply

    Answer:

    20.2 amu.

    Explanation:

    Let A represent isotope ²⁰X

    Let B represent isotope ²²X

    From the question given above, the following data were obtained:

    For Isotope A (²⁰X):

    Mass of A = 20

    Abundance (A%) = 90%

    For Isotope B (²²X):

    Mass of B = 22

    Abundance (A%) = 10%

    Relative atomic mass (RAM) =?

    The relative atomic mass (RAM) of the element can be obtained as follow:

    RAM = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

    RAM = [(20 × 90)/100] + [(22 × 10)/100]

    RAM = 18 + 2.2

    RAM = 20.2 amu

    Thus, relative atomic mass (RAM) of the element is 20.2 amu

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )