What is the maximum wavelength of incident light for which photoelectrons will be released from gallium

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What is the maximum wavelength of incident light for which photoelectrons will be released from gallium

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Acacia 4 years 2021-08-05T08:53:45+00:00 1 Answers 84 views 0

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  1. thugiang
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    2021-08-05T08:54:53+00:00
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    Answer:

    292 nm

    Explanation:

    The work function of gallium ∅ = 94.25 eV = 6.81 x 10^-19 J

    at maximum wavelength, the energy of the photons is equal to its work function

    Energy of the electron = hf

    but hf = hc/λ

    where h is the planck’s constant = 6.63 × 10-34 m^2 kg/s

    c is the speed of light = 3 x 10^8 m/s

    λ is the wavelength that this occurs, which is the maximum wavelength

    Equating, we have

    hc/λ =  ∅

    substituting, we have

    (6.63 × 10-34 x 3 x 10^8)/λ = 6.81 x 10^-19

    (1.989 x 10^-25)/(6.81 x 10^-19) = λ

    λ = 292.07 x 10^-9 = 292 nm

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