What is the Kc for the following reaction at equilibrium at 800∘C if [CO2]= 0.030 M ? CaCO3(s)⇌CaO(s)+CO2(g)

Question

What is the Kc for the following reaction at equilibrium at 800∘C if [CO2]= 0.030 M ? CaCO3(s)⇌CaO(s)+CO2(g)

in progress 0
Thu Hương 4 years 2021-09-04T12:10:17+00:00 1 Answers 18 views 0

Answers ( )

    0
    2021-09-04T12:11:34+00:00

    Answer:

    0.030

    Explanation:

    Step 1: Write the balanced reaction at equilibrium

    CaCO₃(s) ⇌ CaO(s) + CO₂(g)

    Step 2: Calculate the concentration equilibrium constant

    The concentration equilibrium constant (Kc) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It doesn’t include solids or pure liquids.

    Kc = [CO₂] = 0.030

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )