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What is produced at each electrode in the electrolysis of an aqueous solution of both nabr and agf?
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Answer:
Explanation:
reduction potential of Ag+/Ag = 0.80 V
the oxidation potential of Br-/Br2 = -1.066 V
reduction potential of Na+/Na = 2.71 V
reduction potential of 2H+/H2 = 0.00 V
oxidation potential of 2F-/F2 = -2.87 V
oxidation potential of 2H2O↔ O2 + 4H+ + 4e- = -1.23 V
So, at cathode reduction occurs so, here Ag(s) will form because it has high reduction potential.
However, at anode oxidation occurs and , here the substance with high oxidation potential can oxidises easily so bromine will form.