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What change should be expected in the velocity of a body to maintain the same kinetic energy, if its mass is increased sixteen times? H
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Answer:
firstly,
ke=1÷2mv^2
on putting same ke by increasing mass by 16 times new velocity becomes v’
then
ke=1÷2×16m×v’^2
from above we can write
1÷2mv^2=1÷2×16m×v’^2
v^2=16v’^2
1÷4v=v’
hence original velocity should be decreased by 4 times to keep same ke