Using the formula W = mg, how many milliliters of water with a density of 1g/mL are required to weigh 0.75 newtons and g = 9.81 m/s2? Round

Question

Using the formula W = mg, how many milliliters of water with a density of 1g/mL are required to weigh 0.75 newtons and g = 9.81 m/s2? Round to the nearest tenth. (Note: The mass will be in kg in your answer, thus convert to g and then to mL.) Answer: mL

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Farah 3 years 2021-08-19T08:45:33+00:00 2 Answers 34 views 0

Answers ( )

  1. thienhuong
    0
    2021-08-19T08:47:23+00:00
    Reply

    Given that,

    Weight = 0.75 N

    Acceleration due to gravity = 9.81 m/s²

    Density of water = 1 g/ml

    We need to calculate the volume of water

    Using formula of weight

    W=mg

    W=\rho Vg

    mg=\rho\times V\times g

    Where, V = volume

    g = acceleration

    m = mass

    Put the value into the formula

    0.076\times 9.8\times10^3=1\times V\times9.8

    V= \dfrac{0.076\times 9.8\times10^3}{1\times9.8}

    V=76\ ml

    Hence, The volume of water is 76 mL.

  2. ngockhue
    0
    2021-08-19T08:47:27+00:00
    Reply

    Answer:

    76.5mL

    Explanation:

    w = mg

    0.75N = m * 9.81

    m = 0.75 / 9.81 = 0.0765 kg

    The mass in grams is 0.0765 * 1000 = 76.5g

    At a density of 1 g/mL,

    76.5g ÷ 1g/ml = 76.5mL

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