Two speakers, one directly behind the other, are each generating a 280-Hz sound wave. What is the smallest separation distance between the s

Question

Two speakers, one directly behind the other, are each generating a 280-Hz sound wave. What is the smallest separation distance between the speakers that will produce destructive interference at a listener standing in front of them? The speed of sound is 338 m/s.

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Mít Mít 4 years 2021-08-05T09:34:03+00:00 1 Answers 33 views 0

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    2021-08-05T09:35:34+00:00

    Answer:

    1.21m

    Explanation:

    If two speakers are generating a frequency of 280Hz, the smallest separation distance between the speakers that will produce destructive interference at a listener standing in front of them is also known as the wavelength of the sound wave generated.

    Using the expression;

    Velocity v = frequency f × wavelength ¶

    Given frequency = 280Hz, speed of sound v = 338m/s

    Substituting this data’s in the expression given to get the wavelength will give;

    ¶ = v/f

    ¶ = 338/280

    ¶ = 1.21m

    The smallest separation between the speakers that will produce the interference is 1.21m

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