Two people are competing in a tubing competition. They push a 132 kg inner tube. If the combined push of the team is 450 N and the inn

Question

Two people are competing in a tubing competition. They push a 132 kg inner
tube. If the combined push of the team is 450 N and the inner tube also
experiences a friction force of 35 N, what is the acceleration of the inner tube? (F
=ma)

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King 4 years 2021-09-04T18:12:27+00:00 1 Answers 13 views 0

Answers ( )

  1. kimcuc
    0
    2021-09-04T18:13:50+00:00
    Reply

    Answer:

    a=3.14\ m/s^2

    Explanation:

    Given that,

    Mass of the tube, m = 132 kg

    Force = 450 N

    Friction force, f = 35 N

    Net force,

    F = 450 – 35

    F = 415 N

    Let a be the acceleration. We know that,

    F = ma

    a=\dfrac{F}{m}\\\\a=\dfrac{415}{132}\\\\a=3.14\ m/s^2

    So, the acceleration is 3.14\ m/s^2.

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