Two people are carrying a uniform 704.0 N log through the forest. Bubba is 2.2 m from one end of the log (x), and his partner is 0.9 m from

Question

Two people are carrying a uniform 704.0 N log through the forest. Bubba is 2.2 m from one end of the log (x), and his partner is 0.9 m from the other end (y). The log is 6.2 m long (z). What weight is Bubba supporting

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Thiên Ân 4 years 2021-08-05T20:58:27+00:00 1 Answers 17 views 0

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  1. Sigrid
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    2021-08-05T20:59:27+00:00
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    Answer:

    F₁ = 499.61 N , this is the force that Bubba support

    Explanation:

    The trunk is in equilibrium with the two forces applied by man, let’s use the equilibrium relation

    let’s set a reference frame at the extreme left and assume that the counterclockwise rotations are positive

    Let’s write the expression for the translational equilibrium

    subscript 1 is for Bubba’s mass and subscript 2 for his partner

                   F₁ + F₂ -W = 0

                    F₁ + F₂ = W

    the expression for rotational equilibrium

                   ∑ τ = 0

                   F₁  2.2 + F₂  (6.2-0.9) – W  6.2/2 = 0

                   2.2 F1 + 5.3 F2 = 3.1 W

    let’s write our system of equations

                 F₁ + F₂ = W

                 2.2 F₁ + 5.3 F₂ = 3.1 W

    we solve for F₁ in the first equation and substitute in the second

                F₁ = W-F₂

                2.2 (W- F₂) + 5.3 F₂ = 3.1 W

                F₂ ( -2.2 +5.3) = W (3.1 – 2.2)

                F₂ = 704  0.9 / 3.1            

                F₂ = 204.39 N

    This is the force that the partner supports

    we look for F1

                F₁ = W-F₂

                F₁ = 704 – 204.39

                 F₁ = 499.61 N

    This is the force that Bubba support

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )