Two diamonds begin a free fall from rest from the same height 0.9 s apart. How long after the first object begins to fall will the two objec

Question

Two diamonds begin a free fall from rest from the same height 0.9 s apart. How long after the first object begins to fall will the two objects be 13 m apart

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Thành Công 4 years 2021-09-01T00:35:04+00:00 1 Answers 34 views 0

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  1. Vodka
    0
    2021-09-01T00:36:20+00:00
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    The time taken is 1 second

    Explanation:

    Suppose the first diamond falls for t seconds

    The downward displacement S₁ = u t + \frac{1}{2} g t²

    here u = 0 , because it was at rest initially

    Thus S₁ = \frac{1}{2} g t²              I

    Similarly second diamond moves for time ( t – 0.9 ) sec

    The distance covered by it is

    S₂ = \frac{1}{2} g (t – 0.9 )²

    The separation between the two is 13 m

    Thus S₁ – S₂ = 13 m

    \frac{1}{2} g t² – \frac{1}{2} g t² + 0.9 g t – 0.4 g = 13

    or  9 t = 13 – 4 = 9

    Hence t = 1 sec

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