Tired of being chased by a jaguar, you set a trap. Hoping to drop it on the jaguar, you try to push a 44.0 kg stone boulder off

Question

Tired of being chased by a jaguar, you set a trap. Hoping to drop it on the jaguar, you try to push a

44.0 kg stone boulder off of the edge of a cliff that slopes down at an angle of 15.0°. Being weak with

hunger, the best you can do is push the boulder with a force of 222 N. The coefficient of kinetic friction

between the boulder and the ground is is 0.700. (Ignore static friction.)

What is the acceleration of the boulder while you push it down the incline?

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Thu Thủy 4 years 2021-09-03T19:04:46+00:00 1 Answers 11 views 0

Answers ( )

  1. MichaelMet
    0
    2021-09-03T19:06:17+00:00
    Reply

    Answer: acceleration = 3.27m/s^2

    Explanation:

    Given that the

    Mass M = 44kg

    Angle Ø = 15 degree

    Coefficient of friction ų = 0.7

    Force F = 222N

    F – Fr = ma …… (1)

    Where Fr = frictional force

    Fr = ųN

    N = normal reaction = mg

    Fr = ųmgsinØ

    Fr = 0.7 × 44 × 9.81 × sin 15

    Fr = 78.2N

    Substitutes Fr, F and M into equation one.

    222 – 78.2 = 44a

    143.79 = 44a

    Make a the subject of formula

    a = 143.79/44

    Acceleration a = 3.27 m/s^2

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