Three forces act on a statue. Force F⃗ 1F→1 (magnitude 45.0 NN) points in the +x-direction, Force F⃗ 2F→2 (magnitude 105 NN) points in the +

Question

Three forces act on a statue. Force F⃗ 1F→1 (magnitude 45.0 NN) points in the +x-direction, Force F⃗ 2F→2 (magnitude 105 NN) points in the +y-direction, and force F⃗ 3F→3 (magnitude 235 NN) is at an angle of 36.9∘∘ from the -x-direction and 53.1∘∘ from the +y-direction. counterclockwise from the +x-direction. Find the x- and y-components of the net external force F⃗ F→ on the statue

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Vân Khánh 3 years 2021-08-24T14:42:40+00:00 1 Answers 153 views 0

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  1. thucuc
    0
    2021-08-24T14:44:38+00:00
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    Answer:

    Resultant force = (232.93î + 246.10j) N

    x-component of the resultant force = (+232.93î) N

    y-component of the resultant force = (+246.1j) N

    Explanation:

    The net external force on the statue is equal to the resultant force on the statue.

    And the resuphant force is a vector sum of all the other forces acting on the statue.

    Force 1 = (45î) N

    Force 2 = (105j) N

    Force 3 = (235cos 36.9°)î + (235 sin 36.9°)j = (187.93î + 141.10j) N

    Resultant force = (Force 1) + (Force 2) + (Force 3)

    Resultant force = 45î + 105j + (187.93î + 141.10j) = (232.93î + 246.10j) N

    Hope this helps!!!

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