The width of Field A is 7/12 of its length of 108 m. What is the perimeter of Field B if it has 5/6 of the perimeter of Field A?

Question

The width of Field A is 7/12 of its length of 108 m. What is the perimeter of Field B if it has 5/6 of the perimeter of Field A?

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Dâu 4 years 2021-09-03T23:33:20+00:00 1 Answers 10 views 0

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  1. Calantha
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    2021-09-03T23:34:52+00:00
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    Answer: (100th answer)

    perimeter of field b = 260 m

    Step-by-step explanation:

    First we have to find what is 7/12 of 108?

    Well first we need to know what 1/12 of 108 is. Which means we do 108/12. That equals 9. so if 1/12 of 108 = 9

    then 7/12 of 108 is 9*7 which is 63.

    The width of field A is 63 plus its length, width again and its length again would be its perimeter or

    2l + 2w is its perimeter, where l is length and w is width

    108*2+63*2= perimeter

    216+126 = ?

    342 is the perimeter of field A.

    We aren’t done though.

    We have to find 5/6 of 342.

    1/6 of 342 is 342/6

    342/6 = 52

    1/6 of 342 = 52 meaning 5/6 of 342 is equal to 5*52.

    5*52 = 260

    the perimeter of field b is 260

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