The sum of two numbers is 47. twice the first number and three times the second number have a sum of 100. Set up a system of equations to fi

Question

The sum of two numbers is 47. twice the first number and three times the second number have a sum of 100. Set up a system of equations to find the numbers

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Verity 4 years 2021-08-23T03:12:55+00:00 2 Answers 24 views 0

Answers ( )

  1. Farah
    0
    2021-08-23T03:14:09+00:00
    Reply

    Answer:

    23

    Step-by-step explanation:

  2. Helga
    0
    2021-08-23T03:14:18+00:00
    Reply

    x + y = 47

    2x + 3y = 100

    Solving steps

    x + y = 47 (-2)

    2x + 3y = 100

    We multiply the first equation by -2. This is so that x changes to -2x (So it would match the x below). We can then cross it over, since the equation below has 2x and -2x + 2x = 0.

    -2x – 2y = -94

    2x + 3y = 100

    Y = 6

    We get y = 6 by subtracting -2y (From the above equation) from 3y. This gives us Y. Afterwards, We subtract -94 (From the above equation) from 100 and that gives us 6. Therefore, y = 6.

    To get x. We sub in the value for y into one of the equations and solve.

    2x + 3(6) = 100

    2x + 18 = 100

    We bring over 18 from one side to the other, to get x alone. We have to change 18 to – 18 because it crosses over to the other side.

    2x = 100 – 18

    2x = 72

    x = 72÷2

    x = 36.

    X = 36

    Y = 6

    (36, 6)

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )