The strengths of the fields in the velocity selector of a Bainbridge mass spectrometer are B=0.500 T and E=1.2×105 V/m. The strength of the

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The strengths of the fields in the velocity selector of a Bainbridge mass spectrometer are B=0.500 T and E=1.2×105 V/m. The strength of the magnetic field that seperates the ions is Bo=0.750 T. A stream of single charged Li ions is found to bend in a circular arc of radius 2.32 cm. What is the mass of the Li ions?

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Thành Đạt 5 years 2021-07-14T07:05:53+00:00 1 Answers 122 views 0

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  1. ngocdiep
    0
    2021-07-14T07:07:37+00:00
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    Answer:

    m = 1.16 \times 10^{-26}\ Kg

    Explanation:

    Given,

    Magnetic field, B = 0.5 T

    Electric field, E = 1.2 x 10⁵ V/m

    strength of the magnetic field that separates the ions, Bo=0.750 T

    Radius, r = 2.32 cm

    Relation of charge to mass ratio is given by

    \dfrac{q}{m}=\dfrac{E}{BB_0R}

    m=\dfrac{qBB_0R}{E}

    Substituting all the values

    m=\dfrac{1.6\times 10^{-19}\times 0.5\times 0.75\times 02.0232}{1.2\times 10^5}

    m = 1.16 \times 10^{-26}\ Kg

    Mass of Li ions is equal to m = 1.16 \times 10^{-26}\ Kg

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