. The speedometer readings of a car are shown below. Find the acceleration of the car and its displacement. Time 9:25 am 9:45 am

Question

. The speedometer readings of a car are shown below. Find the acceleration of the car and its displacement.
Time
9:25 am 9:45 am
Speedometer
36 km/h 72 km/h

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Vodka 5 years 2021-07-27T07:11:43+00:00 1 Answers 202 views -1

Answers ( )

    0
    2021-07-27T07:13:39+00:00

    It is given that u=36km/h

    V= 72km/h

    We have to convert it into m/s ao we will multiply it with 5/18

    U=36×5/18=10

    V=72×5/18=20

    So acceleration =v-u/t

    = 20-10/t

    The time will be 9:45-9:25=20min

    So we will convert it into second

    = 20×60

    a=20-10/20×60

    =10/20×60

    1/120

    From  newtons 2nd law

    V^2-u^2=2as

    S=v^2-u^2/2a

    =400-100×120/2

    =18000m/s

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