The quantity y varies directly with the square of x. If y=24 when x=3, find y when x is 4

Question

The quantity y varies directly with the square of x. If y=24 when x=3, find y when x is 4

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Thiên Ân 3 years 2021-08-22T16:34:17+00:00 1 Answers 11 views 0

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  1. RobertKer
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    2021-08-22T16:35:27+00:00
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    Answer:

    y = \frac{384}{9}

    Step-by-step explanation:

    Given

    y\ \alpha\ x^2 — direct variation

    (x,y) = (3,24)

    Required

    y when x = 4

    y\ \alpha\ x^2

    Express as an equation

    y = kx^2

    Substitute: (x,y) = (3,24)

    24 = k*3^2

    24 = k*9

    Solve for k

    k = \frac{24}{9}

    To solve for y when x = 4, we have:

    y = kx^2

    y = \frac{24}{9} * 4^2

    y = \frac{24}{9} * 16

    y = \frac{24 * 16}{9}

    y = \frac{384}{9}

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