The perimeter of a parallelogram must be no less than 40 feet. The length of the rectangle is 6 feet. What are the possible measurements of

Question

The perimeter of a parallelogram must be no less than 40 feet. The length of the rectangle is 6 feet. What are the possible measurements of the width? Write an inequality to represent this problem. Use w to represent the width of the parallelogram. [Hint: The formula for finding the perimeter of a parallelogram is P = 2 l + 2 w . What is the smallest possible measurement of the width? Justify your answer by showing all your work.

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Delwyn 3 years 2021-08-30T14:28:57+00:00 1 Answers 1 views 0

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  1. hongcuc2
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    2021-08-30T14:30:47+00:00
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    Answer: 14\ ft

    Step-by-step explanation:

    Given

    Length of rectangle is 6\ ft

    Perimeter must be greater than 40 ft

    Suppose l and w be the length and width of the rectangle

    \Rightarrow \text{Perimeter P=}2(l+w)\\\Rightarrow P\geq 40\\\Rightarrow 2(l+w)\geq40\\\Rightarrow l+w\geq20\\\Rightarrow w\geq20-6\\\Rightarrow w\geq14\ ft

    So, the smallest width can be 14\ ft

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )