The gas phase decomposition of nitrogen dioxide at 383 °C NO2(g)NO(g) + ½ O2(g) is second order in NO2 with a rate c

Question

The gas phase decomposition of nitrogen dioxide at 383 °C

NO2(g)NO(g) + ½ O2(g)

is second order in NO2 with a rate constant of 0.540 M-1 s-1.
If the initial concentration of NO2 is 0.477 M, the concentration of NO2 will be
M after 12.4 seconds have passed.

in progress 0
Thu Thảo 3 years 2021-08-30T17:04:03+00:00 1 Answers 27 views 0

Answers ( )

  1. Cherry
    1
    2021-08-30T17:05:12+00:00
    Reply

    Answer:

    [NO_2]=0.112M

    Explanation:

    Hello there!

    In this case, since the second-order integrated law is given by the following equation:

    \frac{1}{[NO_2]} =\frac{1}{[NO_2]_0}+kt

    Thus, given the initial concentration of the nitrogen dioxide gas, the rate constant and the elapsed time, we obtain:

    \frac{1}{[NO_2]}= \frac{1}{0.477M} +0.54M^{-1}s^{-1}\\\\\frac{1}{[NO_2]}=8.933M^{-1}

    [NO_2]=\frac{1}{8.933M^{-1}} =0.112M

    Best regards!

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )