The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volume of the ba

Question

The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volume of the balloon? (Hint: n and P are constant) (Unit= m^3)

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Latifah 4 years 2021-08-16T00:01:20+00:00 1 Answers 31 views 0

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  1. Doris
    0
    2021-08-16T00:02:40+00:00
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    Answer:

    \boxed{ V_{2}= 0.03189 m^3}

    Explanation:

    According to Charles Law

    => \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}

    Where V_{1} = 0.0279 m³, T_{1} = 280 K and T_{2} = 320 K

    => \frac{0.0279}{280} = \frac{V_{2}}{320}

    => V_{2} = 0.03189 m³

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