The function f(n)=100(0.25)^n represents the amount of radioactive substance left after n hours. At what rate in percent is the amount of ra

Question

The function f(n)=100(0.25)^n represents the amount of radioactive substance left after n hours. At what rate in percent is the amount of radioactive substance changing

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Xavia 4 years 2021-07-28T22:21:18+00:00 1 Answers 59 views 0

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  1. thuhuong
    0
    2021-07-28T22:22:21+00:00
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    Answer:

    75%

    Step-by-step explanation:

    Given the function :

    f(n)=100(0.25)^n

    Comparing the function with

    y = a(1 – r)^t

    From. The equation, r = rate

    Comparing with the value in bracket in the question given :

    1 – r = 0.25

    1 – 0.25 = r

    0.75 = r

    Hence, r = 0.75

    As a percentage, rate = 0.75 * 100% = 75%

    Hence, the rate of change is 75%

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