The equilibrium constant (K) for the reaction 2HCI(g) = H2(g) + Cl2(g) is 4.17 x 10-34 at 25°C. What is the equilibrium constant

Question

The equilibrium constant (K) for the reaction
2HCI(g) = H2(g) + Cl2(g)
is 4.17 x 10-34 at 25°C. What is the equilibrium constant for the reverse reaction at the same
temperature?
H2(g) + Cl2(g) = 2HCl(g)

in progress 0
Vân Khánh 4 years 2021-07-20T20:13:33+00:00 1 Answers 49 views 0

Answers ( )

  1. thuthuy
    0
    2021-07-20T20:15:05+00:00
    Reply

    Answer: The equilibrium constant for the reverse reaction at the same temperature is 2.40 \times 10^{33}.

    Explanation:

    The given reaction equation is as follows.

    2HCl(g) \rightleftharpoons H_{2}(g) + Cl_{2}(g) … (1)

    It’s equilibrium constant (K) value is 4.17 \times 10^{-34}.

    Also, another reaction equation is as follows.

    H_{2}(g) + Cl_{2}(g) \rightleftharpoons 2HCl(g)

    This is the reverse of equation (1). Hence, its equilibrium value is calculated as follows.

    K' = \frac{1}{K}\\= \frac{1}{4.17 \times 10^{-34}}\\= 2.40 \times 10^{33}

    Thus, we can conclude that the equilibrium constant for the reverse reaction at the same temperature is 2.40 \times 10^{33}.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )