The expression 16t^2 represents the distance in feet the object falls after t seconds. The object is dropped from a height of 906 feet. What

Question

The expression 16t^2 represents the distance in feet the object falls after t seconds. The object is dropped from a height of 906 feet. What is the height in feet of the object 2 seconds after it is dropped?

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Sigridomena 4 years 2021-08-18T14:04:21+00:00 2 Answers 7 views 0

Answers ( )

  1. niczorrrr
    0
    2021-08-18T14:06:00+00:00
    Reply

    Answer:842

    Step-by-step explanation:

  2. thongdat2
    0
    2021-08-18T14:06:00+00:00
    Reply

    Answer:

    824 feet

    Step-by-step explanation:

    Given

    h(t) = 16t^2

    H = 906 — Initial Height

    Required

    Determine its height after 2 seconds

    First, we calculate the distance covered in 2 seconds

    h(t) = 16t^2

    h(2) = 16*2^2

    h(2) = 16*4

    h(2) = 64

    This means that the object moved a distance of 64feet

    So, the object height is calculate by subtracting the distance covered from the object’s initial height:

    i.e.

    Height = H - h(2)

    Height = 906- 64

    Height = 824

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