The electronics supply company where you work has two different resistors, R1 and R2, in its inventory, and you must measure the values of t

Question

The electronics supply company where you work has two different resistors, R1 and R2, in its inventory, and you must measure the values of their resistances. Unfortunately, stock is low, and all you have are R1 and R2 in parallel and in series – and you can’t separate these two resistor combinations. You separately connect each resistor network to a battery with emf 39.0 V and negligible internal resistance and measure the power P supplied by the battery in both cases. For the series combination, P = 48.0 W; for the parallel combination, P = 256 W. You are told that R1>R2.

Calculate R1

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Thu Giang 4 years 2021-08-02T19:50:40+00:00 1 Answers 184 views 0

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  1. Cherry
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    2021-08-02T19:51:40+00:00
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    Answer:

    R₁ = 23.77 ohms and R₂ = 7.92 ohms

    Explanation:

    When connected in series, the equivalence resistance, R(eq) is given as

    R(eq) = (R₁ + R₂)

    When connected in parallel, the equivalence resistance, R(eq) is given as

    [1/R(eq)] = [(1/R₁) + (1/R₂)]

    R(eq) = (R₁R₂)/(R₁ + R₂)

    The parallel and series combination are connected to a battery of emf 39.0 V with negligible internal resistance. And the power supplied is measured.

    But power supplied is given as

    P = IV = (V/R) V = (V²/R)

    When connected in series, the power supplied is given as

    P = 48.0 W,

    V = 39.0 V,

    R = R(eq) = (R₁ + R₂)

    48 = (39²/R)

    R = (39²/48)

    R = 31.6875 ohms

    R = (R₁ + R₂) = 31.6875

    (R₁ + R₂) = 31.6875 (eqn 1)

    When connected in series, the power supplied is given as

    P = 256.0 W,

    V = 39.0 V,

    R = R(eq) = (R₁R₂)/(R₁ + R₂)

    256 = (39²/R)

    R = (39²/256)

    R = 5.9414 ohms

    R = R(eq) = (R₁R₂)/(R₁ + R₂) = 5.9414

    (R₁R₂)/(R₁ + R₂) = 5.9414

    But, recall eqn 1

    (R₁ + R₂) = 31.6875

    (R₁R₂)/(R₁ + R₂) = 5.9414

    Substituting for (R₁ + R₂)

    (R₁R₂)/(R₁ + R₂) = (R₁R₂)/31.6875 = 5.9414

    (R₁R₂) = 31.6875 × 5.9414 = 188.2683

    R₁ = (188.2683/R₂)

    (R₁ + R₂) = 31.6875

    Substituting for R₁

    (188.2683/R₂) + R₂ = 31.6875

    multiply through by R₂

    188.2683 + R₂² = 31.6875R₂

    R₂² – 31.6875R₂ + 188.2683 = 0

    Solving the quadratic equation

    R₂ = 23.77 ohms or 7.92 ohms

    If R₂ = 23.77 ohms, R₁ = 7.92 ohms

    If R₂ = 7.92 ohms, R₁ = 23.77 ohms

    Since the question explains that R₁ > R₂

    R₁ = 23.77 ohms and R₂ = 7.92 ohms

    Hope this Helps!!!

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