The electric potential in a particular region of space varies only as a function of y-position and is given by the function V(y)1.69y2 +15.6

Question

The electric potential in a particular region of space varies only as a function of y-position and is given by the function V(y)1.69y2 +15.6y 52.5) Volts. Calculate the magnitude of the electric field at the position y – 22.5 meters

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Minh Khuê 3 years 2021-08-18T21:12:27+00:00 1 Answers 16 views 0

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    2021-08-18T21:13:32+00:00

    Answer:

    E = 55.9583\ Volts/meter

    Explanation:

    First let’s find the electric potential using y = 22.5:

    V(y) = 1.69y^2 +15.6y+52.5

    V(22.5) = 1.69(22.5)^2 + 15.6*22.5 + 52.5

    V(22.5) = 1259.0625\ Volts

    Then, to find the magnitude of the electric field, we just need to divide the electric potential by the distance y:

    E = V/d

    E = 1259.0625/22.5

    E = 55.9583\ Volts/meter

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