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Suppose you need to prepare 21.0 mL of formate buffer with a ratio of 4 of [sodium formate]/[formic acid] by mixing 0.10 M formic acid and 0
Question
Suppose you need to prepare 21.0 mL of formate buffer with a ratio of 4 of [sodium formate]/[formic acid] by mixing 0.10 M formic acid and 0.10 M sodium formate. How many milliliters of sodium formate do you need to measure to make this buffer (assuming the rest is formic acid)
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Chemistry
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2021-07-17T03:11:15+00:00
2021-07-17T03:11:15+00:00 1 Answers
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Answer: A volume of 20.49 milliliters of sodium formate do you need to measure to make this buffer (assuming the rest is formic acid).
Explanation:
Given: Total volume of the buffer = 21.0 mL
It is assumed that the volume of HCOONa is x. Hence, volume of HCOOH is (21.0 – x) mL.
Hence,
[HCOONa] = Molarity
Volume
= 0.10
x
= 0.1x mmol
Similarly, [HCOOH] = Molarity
Volume
= 0.10
(21.0 – x) mmol
Using equation (1),
As x is the volume of sodium formate. Hence, 20.49 mL of sodium formate is required to make the buffer.
Thus, we can conclude that a volume of 20.49 milliliters of sodium formate do you need to measure to make this buffer (assuming the rest is formic acid).