Suppose that the rod in Fig. 17.24a is made of copper, is 45.0 cm long, and has a cross-sectional area of 1.25 cm2. Let TH = 100.0°C and TC

Question

Suppose that the rod in Fig. 17.24a is made of copper, is 45.0 cm long, and has a cross-sectional area of 1.25 cm2. Let TH = 100.0°C and TC = 0.0°C. (a) What is the final steady-state temperature gradient along the rod? (b) What is the heat current in the rod in the final steady state? (c) What is the final steady-state temperature at a point in the rod 12.0 cm from its left end?

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Delwyn 4 years 2021-08-31T12:58:37+00:00 1 Answers 64 views 0

Answers ( )

  1. nguyetanh
    0
    2021-08-31T12:59:44+00:00
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    Answer: a) 222k/m

    b) 42.5W

    c) if cold: 26.7C

    If hot: 73.3C

    Explanation:

     If TH and TC are at the ends of the rod in the figure, then;

    (A) 100 K / 45 cm = 2.22 K/cm or 222 K/m

    (B) thermal conductivity constant for copper is 390 W/(m K).

    Then the heat flow rate = Q/t

    Q/t = [390 W/(m K)] (100 K) [ pi (0.0125 m)^2 ] / (0.45 m) 

    = 42.5 watts

    (C) 12/45 = 4/15 = 0.2667

    If the left end is the cold end, the answer will be 26.7 C

    If the left end is the hot end, the answer will be 73.3 C

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