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Suppose that a wave forms in shallow water. Then the depth d of the water (in meters) and the velocity v of the wave (in meters per second)
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Suppose that a wave forms in shallow water. Then the depth d of the water (in meters) and the velocity v of the wave (in meters per second) are related by the equation =v9.8d. If a wave formed in shallow water has a velocity of 5.2 meters per second, what is the water’s depth? Carry your intermediate computations to at least four decimal places, and round your answer to the nearest tenth.
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3 years
2021-07-27T14:24:06+00:00
2021-07-27T14:24:06+00:00 1 Answers
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Answers ( )
The clear question is;
Suppose that a wave forms in shallow water. Then the depth d of the water (in meters) and the velocity v of the wave (in meters per second) are related by the equation v=√9.8d . If the wave formed in shallow water has a velocity of 5.2 meters per second, what is the water’s depth? Carry your intermediate computation to at least four decimal places, and round your answer to the nearest tenth
Answer:
Water’s depth;d ≈ 2.8 m
Explanation:
We are told that the relationship between the velocity and depth of the water is given by;
v = √9.8d
Where;
v is the velocity of the wave and d is the depth of the water
Now, we are given velocity; v = 5.2 m/s.
Thus, plugging it into the relation above, we have;
5.2 = √9.8d
Let’s take the square of both sudes to get;
5.2² = 9.8d
27.04 = 9.8d
Let’s divide both sides by 9.8 to get;
9.8d/9.8 = 27.04/9.8
d = 2.7592m
We are told to approximate to nearest tenth.
Thus, d ≈ 2.8 m