Suppose 6 pints of a 28% alcohol solution is mixed with 4 pints of a 90% alcohol solution. What is the concentration of alcohol in the new 1

Question

Suppose 6 pints of a 28% alcohol solution is mixed with 4 pints of a 90% alcohol solution. What is the concentration of alcohol in the new 10-pint mixture?
The concentration of alcohol in the new 10-pint mixture is 3%.

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Lệ Thu 4 years 2021-08-16T10:48:21+00:00 1 Answers 14 views 0

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  1. Philomena
    0
    2021-08-16T10:50:01+00:00
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    Answer:

    52.8%

    Step-by-step explanation:

    The amount of alcohol is:

    0.28 (6 pints) + 0.90 (4 pints) = 5.28 pints

    So the concentration is:

    5.28 pints / 10 pints × 100% = 52.8%.

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