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Solve the following numerical problems. a) A load of 400N is liſted up by an effort of 100N. If load distance is 20cm, what will be the effo
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Answer:
Solution
Load(L)=400
Effort(E)=100
Load distance (Ld)=20cm
Effort distance(Ed)=?
Now,from the principle of equilibrium
L×Ld=E×Ed
or,Ed=L×Ld/E
or,Ed=400×20/100
:.Ed=80cm and
Therefore,the effort distance will be 80cm