x²+y²-6x+14y-1=0 and please show your work so I can learn

Question

x²+y²-6x+14y-1=0
and please show your work so I can learn

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Thanh Thu 4 years 2021-07-30T04:06:12+00:00 1 Answers 13 views 0

Answers ( )

  1. thucuc
    0
    2021-07-30T04:07:37+00:00
    Reply

    Hello there,

    I hope you and your family are staying safe and healthy during this winter season.

    x^2 + y^2 -6x+14y-1=0

    We need to use the Quadratic Formula*

    x =\frac{-b+\sqrt{b^2}-4ac }{2a} , \frac{-b-\sqrt{b^2} -4ac }{2a}

    Thus, given the problem:

    a = 1, b=-6, c=y^2+14y-1

    So now we just need to plug them in the Quadratic Formula*

    x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2} , x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}

    As you can see, it is a mess right now. Therefore, we need to simplify it

    x=\frac{6+2\sqrt{10-y^2-14y} }{2}, x = \frac{6-2\sqrt{10-y^2-14y} }{2}

    Now that’s get us to the final solution:

    x=3+\sqrt{10-y^2-14y}, x=3-\sqrt{10-y^2-14y}

    It is my pleasure to help students like you! If you have additional questions, please let me know.

    Take care!

    ~Garebear

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )