Y= 1/3x+3 Y=2x-2 How can I solve of systems of equation substitution.?​

Question

Y= 1/3x+3
Y=2x-2
How can I solve of systems of equation substitution.?​

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Kiệt Gia 4 years 2021-09-04T18:22:41+00:00 1 Answers 18 views 0

Answers ( )

  1. Xavia
    0
    2021-09-04T18:24:39+00:00
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    Answer:

    x=3, Y= 4

    Step-by-step explanation:

    ① Label the 2 equations

    Y= ⅓x +3 —–(1)

    Y= 2x -2 —–(2)

    ② Since both equations are Y= ____, substitute one equation into the other so that we are left with x terms and constant only.

    subst. (1) into (2):

    ⅓x +3= 2x -2

    ③ Bring x terms to one side and constants to the other.

    2x -⅓x= 3 +2

    simplify:

    \frac{5}{3} x = 5

    x = 5 \div \frac{5}{3} \\ x = 5 \times \frac{3}{5} \\ x = 3

    ④ Solve for y.

    Subst. x=3 into (2):

    Y= 2(3) -2

    Y= 6 -2

    Y= 4

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )