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With what tension must a rope with length 2.90 m and mass 0.125 kg be stretched for transverse waves of frequency 42.0 Hz to have a waveleng
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Answers ( )
Answer:
41.64 N
Explanation:
Applying,
v = √(T/m’)……………. Equation 1
Where v = velocity of the wave, T = Tension of the rope, m’ = mass per unit length of the rope.
make T the subject of the equation,
T = v²m’…………….. Equation 2
But,
v = λf…………… Equation 3
Where λ = wavelength, f = frequency
And
m’ = m/L……….. Equation 4
Where m = mass of the rope, L = length of the rope
Substitute equation 3 and equation 4 into equation 2
T = (λf)²(m/L)………….. Equation 5
From the question,
Given: λ = 0.740 m, f = 42 Hz, m = 0.125 kg, L = 2.9 m
Substitute these values into equation 5
T = (42×0.74)²(0.125/2.9)
T = 41.64 N