Which of the following numbers is both a perfect square and a perfect cube? i. 12 544 ii. 531 441 iii. 456 235 This

Question

Which of the following numbers is both a perfect square and a perfect cube?
i. 12 544
ii. 531 441
iii. 456 235
This is really stumping me up

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Orla Orla 4 years 2021-07-22T22:30:36+00:00 2 Answers 111 views 0

Answers ( )

  1. bonexptip
    0
    2021-07-22T22:31:52+00:00
    Reply

    Answer:

    ii. 531441

    Step-by-step explanation:

    Find the prime factorization of each number.

    For a number to be a perfect square, it must have an even number of each factor.

    For a number to be a perfect cube, it must have a multiple of three of each factor.

    i. 12544 = 2^8 * 7^2

    There 8 factors of 2 and 2 factors of 7. The numbers of factors of both 2 and 7 are even, so it’s a perfect square, but neither 8 nor 2 is a multiple of 3, so it is not a perfect cube.

    ii. 531441 = 3^12

    12 is both even and a multiple of 3, so 531441 is a perfect square and a perfect cube.

    iii. 456235 = 5 * 13 * 7019

    No factor is a multiple of 2 or 3, so it is not a perfect square of perfect cube.

    Answer: ii. 531441

  2. Sigrid
    0
    2021-07-22T22:31:58+00:00
    Reply

    Answer:

    531441

    Step-by-step explanation:

    We can find by   factorization

    531441 = 9 * 9 * 9 * 9 * 9 *9 = (9*9*9) * (9*9*9)

    \sqrt[3]{531441}=\sqrt[3]{9*9*9*9*9*9} =9*9 = 81\\\\\\\sqrt{531441}=\sqrt{(9*9)*(9*9)*(9*9)}=9*9*9=729

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