What is the solution set for StartAbsoluteValue 4 minus StartFraction x over 2 EndFraction EndAbsoluteValue = 8? A.x = negative 24 and

Question

What is the solution set for StartAbsoluteValue 4 minus StartFraction x over 2 EndFraction EndAbsoluteValue = 8?
A.x = negative 24 and x = negative 8
B.x = negative 24 and x = 24
C.x = negative 8 and x = 8
D.x = negative 8 and x = 24

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Ngọc Diệp 4 years 2021-09-03T14:32:27+00:00 2 Answers 23 views 0

Answers ( )

  1. King
    0
    2021-09-03T14:33:35+00:00
    Reply

    Answer:

    D

    Step-by-step explanation:

    |4 – x/2| = 8

    solve it first as though there were no absolute value bars

    4 – x/2 = 8

    -x/2 = 4

    -x = 8

    x = -8

    now solve it after distributing a negative one

    -(4 – x/2) = 8

    -4 + x/2 = 8

    x/2 = 12

    x = 24

  2. vankhanh
    0
    2021-09-03T14:34:21+00:00
    Reply

    D

    What is the solution set for StartAbsoluteValue 4 minus StartFraction x over 2 EndFraction EndAbsoluteValue = 8?
    A.x = negative 24 and x = negative 8
    B.x = negative 24 and x = 24
    C.x = negative 8 and x = 8
    D.x = negative 8 and x = 24

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )