Using a system of equations, find two numbers whose sum is 26 and whose difference is 12.

Question

Using a system of equations, find two numbers whose sum is 26 and whose difference is 12.

in progress 0
Thu Cúc 4 years 2021-08-05T11:35:48+00:00 1 Answers 25 views 0

Answers ( )

    0
    2021-08-05T11:37:40+00:00

    answer:

    sum: 19 + 7 = 26

    difference: 19 – 7 = 12

    step-by-step explanation:

    the sum of x and y is 26. in other words, x plus y equals 26 and can be written as equation a:

    x + y = 26

    the difference between x and y is 12. in other words, x minus y equals 12 and can be written as equation b:

    x – y = 12

    now solve equation b for x to get the revised equation b:

    x – y = 12

    x = 12 + y

    then substitute x in equation a from the revised equation b and then solve for y:

    x + y = 26

    12 + y + y = 26

    12 + 2y = 26

    2y = 14

    y = 7

    now we know y is 7. this means that we can substitute y for 7 in equation a and solve for x:

    x + y = 26

    x + 7 = 26

    X = 19

    good luck 🙂

    hopefully, this helps

    have a great day !!

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )