The pressure drop needed to force water through a horizontal 1-in diameter pipe if 0.60 psi for every 12-ft length of pipe. Determine shear

Question

The pressure drop needed to force water through a horizontal 1-in diameter pipe if 0.60 psi for every 12-ft length of pipe. Determine shear stress on the pipe wall. Determine the stress at distances 0.3-in and -.5-in away from the pipe wall.

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Nguyệt Ánh 3 years 2021-08-21T19:50:04+00:00 1 Answers 5 views 0

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  1. thienhuong
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    2021-08-21T19:51:49+00:00
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    Answer:

    The shear stress at a distance 0.3-in away from the pipe wall is 0.06012lb/ft²

    The shear stress at a distance 0.5-in away from the pipe wall is 0

    Explanation:

    Given;

    pressure drop per unit length of pipe = 0.6 psi/ft

    length of the pipe = 12 feet

    diameter of the pipe = 1 -in

    Pressure drop per unit length in a circular pipe is given as;

    \frac{\delta P}{L} = \frac{2 \tau}{r} \\\\

    make shear stress (τ) the subject of the formula

    \frac{\delta P}{L} = \frac{2 \tau}{r} \\\\\tau = \frac{\delta P *r}{2L}

    Where;

    τ is the shear stress on the pipe wall.

    ΔP is the pressure drop

    L is the length of the pipe

    r is the distance from the pipe wall

    Part (a) shear stress at a distance of  0.3-in away from the pipe wall

    Radius of the pipe = 0.5 -in

    r = 0.5 – 0.3 = 0.2-in = 0.0167 ft

    ΔP = 0.6 psi/ft

    ΔP, in lb/ft² = 0.6 x 144 = 86.4 lb/ft²

    \tau = \frac{\delta P *r}{2L} = \frac{86.4 *0.0167}{2*12} =0.06012 \ lb/ft^2

    Part (b) shear stress at a distance of  0.5-in away from the pipe wall

    r = 0.5 – 0.5 = 0

    \tau = \frac{\delta P *r}{2L} = \frac{86.4 *0}{2*12} =0

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