The mass of Jupiter is 1.9 × 1027 and that of the sun is 1.99 × 1030. The mean distance of Jupiter from the sun is 7.8 × 1011m.

Question

The mass of Jupiter is 1.9 × 1027 and that of the sun is 1.99 × 1030. The

mean distance of Jupiter from the sun is 7.8 × 1011m. Calculate the gravitational

force which the sun exerts on Jupiter, and the speed of Jupiter.​

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Thu Cúc 4 years 2021-08-25T10:50:04+00:00 1 Answers 8 views 0

Answers ( )

  1. giabao
    0
    2021-08-25T10:51:29+00:00
    Reply

    Answer:

    F = 4.147 × 10^23

    v = 1.31 × 10^4

    Explanation:

    Given the following :

    mass of Jupiter (m1) = 1.9 × 10^27

    Mass of sun (m2) = 1.99 × 10^30

    Distance between sun and jupiter (r) = 7.8 × 10^11m

    Gravitational force (F) :

    (Gm1m2) / r^2

    Where ; G = 6.673×10^-11 ( Gravitational constant)

    F = [(6.673×10^-11) × (1.9 × 10^27) × (1.99 × 10^30)] / (7.8 × 10^11)^2

    F = [25.231 × 10^(-11+27+30)] / (60.84 × 10^22)

    F = (25.231 × 10^46) / (60.84 × 10^22)

    F = 3.235 × 10^(46 – 22)

    F = 0.4147 × 10^24

    F = 4.147 × 10^23

    Speed of Jupiter (v) :

    v = √(Fr) / m1

    v = √[(4.147 × 10^23) × (7.8 × 10^11) / (1.9 × 10^27)

    v = √32.3466 × 10^(23+11) / 1.9 × 10^27

    v = √32.3466× 10^34 / 1.9 × 10^27

    v = √17. 023 × 10^34-27

    v = √17.023 × 10^7

    v = 13047.221

    v = 1.31 × 10^4

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