Share
The displacement of the air molecules in a sound wave is modeled with the wave function s(x, t) = 3.00 nm cos(50.00 m−1x − 1.71 ✕ 104 s−1t).
Question
The displacement of the air molecules in a sound wave is modeled with the wave function s(x, t) = 3.00 nm cos(50.00 m−1x − 1.71 ✕ 104 s−1t). (a) What is the wave speed (in m/s) of the sound wave? 342 Correct: Your answer is correct. m/s (b) What is the maximum speed (in m/s) of the air molecules as they oscillate in simple harmonic motion? m/s (c) What is the magnitude of the maximum acceleration (in m/s2) of the air molecules as they oscillate in simple harmonic motion?
in progress
0
Physics
3 years
2021-09-02T18:06:39+00:00
2021-09-02T18:06:39+00:00 1 Answers
57 views
0
Answers ( )
Answer:
a) 342 m/s
b) 51*10^-6 m/s
c) 0.87m/s^2
Explanation:
The following function describes the displacement of the molecules in a sound wave:
The general form of a function that describes the same situation is:
By comparing equations (1) and (2) you have:
k: wave number = 50.00 m^-1
w: angular frequency = 1.71*10^4 s^-1
A: amplitude of the oscillation = 3.00nm
a) The speed of the sound is obtained by using the formula:
b) The maximum speed of the molecules is the maximum value of the derivative of s(x,t), in time. Then, you first obtain the derivative:
The max value is:
c) The acceleration is the max value of the derivative of the speed, that is, the second derivative of the displacement s(x,t):
Then, the maximum acceleration is: