The current in a circuit is tripled by connecting a 580 resistor in parallel with the resistance of the circuit. Determine the resistance of

Question

The current in a circuit is tripled by connecting a 580 resistor in parallel with the resistance of the circuit. Determine the resistance of the circuit in the absence of the 580 resistor.

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Phúc Điền 3 years 2021-09-05T14:29:19+00:00 1 Answers 41 views 0

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  1. huyenthanh
    0
    2021-09-05T14:31:04+00:00
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    Answer:

    1160 ohm

    Explanation:

    We are given that

    R’=580 ohm

    Current=3 I

    We have to find the resistance of the circuit.

    Let R be the resistance of circuit.

    In parallel

    \frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}

    Using the formula

    \frac{1}{R_{eq}}=\frac{1}{580}+\frac{1}{R}=\frac{580+R}{580R}

    R_{eq}=\frac{580R}{580+R}

    In parallel combination,Potential difference across each resistance remains same.

    V=IR

    Using the formula

    IR=3IR_{eq}

    IR=3I\times \frac{580R}{580+R}

    580+R=3\times 580=1740

    R=1740-580=1160\Omega

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