Suppose you wish to construct a motor that produces a maximum torque whose magnitude is 1.7 × 10-2 N·m. The coil of the motor has an area of

Question

Suppose you wish to construct a motor that produces a maximum torque whose magnitude is 1.7 × 10-2 N·m. The coil of the motor has an area of 9.0 × 10-4 m2, consists of N turns, and contains a current of 1.1 A. The coil is placed in a uniform magnetic field of magnitude 0.20 T. What must N be?

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Thu Thảo 4 years 2021-08-29T12:30:30+00:00 1 Answers 176 views 0

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  1. thienthanh
    0
    2021-08-29T12:31:51+00:00
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    Answer:

    The number of turns in the coil is 86.

    Explanation:

    Given that,

    The magnitude of maximum torque produced in the motor, \tau=1.7\times 10^{-2}\ N-m

    Area of the coil, A=9\times 10^{-4}\ m^2

    Current in the coil, I = 1.1 A

    Magnetic field in the coil, B = 0.2 T

    We need to find the value of N i.e. number of turns in the coil. The magnitude of torque attained in the coil is given by :

    \tau=NIAB\ sin\theta

    Here, \theta=90^{\circ} (maximum)

    \tau=NIAB\\\\N=\dfrac{\tau}{IAB}\\\\N=\dfrac{1.7\times 10^{-2}}{1.1\times 9\times 10^{-4}\times 0.2}\\\\N=85.85\\\\N=86

    So, the number of turns in the coil is 86. Hence, this is the required solution.

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