Suppose to a scientist was able to construct a barometer with a liquid being twice denser than mercury, then how would the liquid raise at s

Question

Suppose to a scientist was able to construct a barometer with a liquid being twice denser than mercury, then how would the liquid raise at standard pressure?​

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Thiên Ân 3 years 2021-09-05T13:57:06+00:00 1 Answers 0 views 0

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  1. ngochoa
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    2021-09-05T13:58:54+00:00
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    Answer:

               h = h₀/2,  the liquid column rises half the height

    Explanation:

    Pressure is defined as force per area,  

             P = F / A

    in a barometer the force is the weights of the liquid column

             F = W = mg

             P = m g/A

    if we use the definition of density

             ρ = \frac{m}{A h}

             \frac{m}{A} = ρ h

    we substitute

             P = ρ g h

    Let’s use the index o for the mercury

             P₀ = ρ₀ g h₀

    when we change the liquid for another with

              ρ = 2ρ₀

    the pressure expression is

             P = 2ρ₀ g h

    in the problem they indicate that the pressure is equal to the initial P = P₀

    we substitute

               ρ₀ g h₀ = 2ρ₀ g h

               h₀ = 2h

               h = h₀/2

    the liquid column rises half the height

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