square root of 80 + square root of 20 divided by square root of 3 in the form of square root a where a is an integer

Question

square root of 80 + square root of 20 divided by square root of 3 in the form of square root a where a is an integer

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Thu Cúc 3 years 2021-09-02T06:39:16+00:00 1 Answers 5 views 0

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  1. ThanhThu
    0
    2021-09-02T06:40:44+00:00
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    Answer:

    2\sqrt{15}

    Step-by-step explanation:

    (\sqrt{80} + \sqrt{20}) ÷ \sqrt{3} =

    = (√4·4·5 + √4·5) ÷ \sqrt{3}

    = (4\sqrt{5} + 2\sqrt{5}) ÷ \sqrt{3}

    = 6\sqrt{5} ÷ \sqrt{3}

    at this point you want to rationalize the denominator, meaning multiply the numerator and denominator by \sqrt{3}

    = (6√5·3) ÷ √3·3

    = 6\sqrt{15} ÷ 3

    = 2\sqrt{15}

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