Solve the equation 2x^{2}-12x-14=x^{2}-8x2x 2 −12x−14=x 2 −8x to the nearest tenth PLEASE HELP

Question

Solve the equation 2x^{2}-12x-14=x^{2}-8x2x 2 −12x−14=x 2 −8x to the nearest tenth

PLEASE HELP

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Thái Dương 3 years 2021-08-21T20:35:43+00:00 1 Answers 17 views 0

Answers ( )

  1. nguyetanh
    0
    2021-08-21T20:37:42+00:00
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    Answer:

    x = 6.2 or -2.2

    Step-by-step explanation:

    Given:

    2x² – 12x – 14 = x² – 8x

    Collect like terms

    2x² – x² – 12x + 8x – 14 = 0

    x² – 4x – 14 = 0

    a = 1

    b = -4

    c = -14

    x = -b ± √b² – 4ac / 2a

    = -(-4) ± √(-4)² – 4(1)(-14) / 2(1)

    = 4 ± √16 -(-56) / 2

    = 4 ± √16 + 56 / 2

    = 4 ± √72 / 2

    = 4 ± 6√2 /2

    = 4/2 + 6√2/2 or 4/2 – 6√2/2

    = 2 + 3√2 or 2 – 3√2

    = 2 + 4.2426406871192 or 2 – 4.2426406871192

    = 6.2426406871192 or -2.2426406871192

    Approximately,

    x = 6.2 or -2.2

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )