Solve 5×2-2x-8=0 using the quadratic formula.

Question

Solve 5×2-2x-8=0 using the quadratic formula.

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Diễm Thu 4 years 2021-09-04T02:16:22+00:00 2 Answers 15 views 0

Answers ( )

  1. minhkhoi
    0
    2021-09-04T02:17:24+00:00
    Reply

    Answer:

    x=\frac{1+\sqrt{41}}{5},\\x=\frac{1-\sqrt{41}}{5}

    Step-by-step explanation:

    The quadratic formula states that the solutions for a quadratic is standard form ax^2+bx+c are equal to x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}.

    In 5x^2-2x-8=0, we can assign the values:

    • a of 5
    • b of -2
    • c of -8

    Thus, we have:

    x=\frac{-(-2)\pm \sqrt{(-2)^2-4(5)(-8)}}{2(5)},\\x=\frac{2\pm \sqrt{164}}{10},\\\begin{cases}x=\frac{2+ \sqrt{164}}{10}, x=\frac{1}{5}+\frac{\sqrt{41}}{5}=\frac{1+\sqrt{41}}{5}\\x=\frac{2- \sqrt{164}}{10}, x=\frac{1}{5}-\frac{\sqrt{41}}{5}=\frac{1-\sqrt{41}}{5}\end{cases}

  2. Dau
    0
    2021-09-04T02:18:12+00:00
    Reply

    Answer:

    (1+√41)/5, (1-√41)/5

    Step-by-step explanation:

    quadratic formula is (-b±√(b^2-4ac))/2a

    in this equation,

    a = 5

    b = -2

    c = -8

    plug in the values

    (2±√(4 – 4(5)(-8))/10

    (2±√(4 + 160)/10

    (2±√(164)/10

    (2±2√(41))/10

    1. (2+2√41)/10

    (1+√41)/5

    2. (2-2√41)/10

    (1-√41)/5

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )