So sánh: 1 + 2 + 2^3 + … + 2^1018 và 2^2019 Giúp mk với!!!

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Question

So sánh: 1 + 2 + 2^3 + … + 2^1018 và 2^2019
Giúp mk với!!!

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Môn Toán Dâu 4 years 2020-10-14T19:34:19+00:00 2020-10-14T19:34:19+00:00 2 Answers 107 views 0

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Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

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King · Answer 1 · 2020-10-14T19:35:19+00:00

King

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2020-10-14T19:35:19+00:00 October 14, 2020 at 7:35 pm

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Đáp án:

Giải thích các bước giải:

A = 1 + 2 + $2^{3}$ + … + $2^{1018}$

2A = 2 + $2^{3}$ + … + $2^{1019}$

2A – A = (2 + $2^{3}$ + … + $2^{1019}$ ) – (1 + 2 + $2^{3}$ + … + $2^{1018}$ )

A = $2^{1019}$ – 1

Ta có $2^{1019}$ – 1 < $2^{2019}$

=> A , $2^{2019}$

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Nick · Answer 2 · 2020-10-14T19:36:10+00:00

Nick

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2020-10-14T19:36:10+00:00 October 14, 2020 at 7:36 pm

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A = 1 + 2 + `2^3` + … + `2^1018`

2A = 2 + `2^3` + … + `2^1019`

2A – A = (2 + `2^3` + … + `2^1019`) – (1 + 2 + `2^3` + … + `2^1018`)

A = `2^1019` – 1

Ta có `2^1019` – 1 < `2^2019`

=> A , `2^2019`

XIN HAY NHẤT Ạ